Question

3.
Show that the sum of the three medians of a
triangle is less than its perimeter.​

Answer 1

Answer:

AB+AC>2AD;. AB+BC>2BE & BC+AC>2CF. Hence, the perimeter of a triangle is greater than the sum of its three medians. Use the result that the perpendicular drawn from a point( outside the line ) to a line is shorter( in length) than a line segment drawn from that point to the line and then add all three cases.

Answer 2

Answer:

I think so it helps you my answers