Question

3) Show the x=1 is a zero of the polynomial 3x³-4x²+8x-7​

Answer 1

substitute 1 in the places of x;

Answer 2

if x = 1 be the zero of the polynomial, then when we substitute this value in the polynomial, then, the remainder would be zero.

$x = 1 \\ p(x) = 3 {x}^{3} - 4 {x}^{2} + 8x - 7 \\ p(1) = 3 {(1)}^{3} - 4 {(1)}^{2} + 8(1) - 7 \\ p(x) = (3 \times 1) - (4 \times 1) + 8 - 7 \\ p(x) = 3 - 4 + 8 - 7 \\ p(x) = - 1 + 1 \\ p(x) = 0$

Hence, x = 1 is a zero of polynomial p(x) 3x³-4x²+8x-7