Question

3) side of
isoscelet
triangle is xe. Find its
right angled
hypotenuse.​

Answer 1

Let ∆PQR be the given right-angled isosceles triangle.

PQ = QR = x.

Step-by-step explanation:

Let ∆PQR be the given right-angled isosceles triangle.

PQ = QR = x. In ∆PQR, ∠Q = 90° [Pythagoras theorem]

∴ PR2 = PQ2 + QR2 = x2 + x2 = 2x2

∴ PR = 2x2−−−√2x2 [Taking square root of both sides] = x2–√2 units

∴ The hypotenuse of the right-angled isosceles triangle is x2–√2 units.

∴ The hypotenuse of the right-angled isosceles triangle is x2–√2 units.