Physics, asked by Mahendraji10981, 2 months ago

3 similar coils each having a resistance of 15 ohm and an inductance of 0.04 h are connected in star to a 3 phase 50 hz supply, 200 v between lines. calculate the line current. if they are now connected in delta, calculate the phase current, line current and the total power absorbed in each phase.

Answers

Answered by pritygupta9162900034
0

answer

200 v

explain

I am very very sorry mujhe nahin pata

Answered by vivekraghuwanshilm
1

Answer:

  • The phase current-4.17A
  • Line current-4.17A
  • Total power absorbed in each phase- 27.13 K W

Explanation:

In a three-phase circuit, there are two types of connections: star and delta. A 4 – wire system is a Star Connection, while a 3 – wire system is a Delta Connection.

Step-1-

Inductive reactance-  X_{L}=2 \pi f L

2 \pi \times 50 \times 40 \times 10^{-3}=12.56\Omega

Phase impedance- Z_{p h}=\sqrt{R^{2}+X_{L}^{2}}

\sqrt{15^{2}+12.56^{2}} = 27.56

Line voltage - V_{\text {line }}=\sqrt{3} V_{p h} = V_{p h}=\frac{V_{\text {line }}}{\sqrt{3}}

\frac{200}{\sqrt{3}}=115V

Phase current and line current - I_{p h}=\frac{V_{p h}}{Z_{p h}} = 4.17A

I_{\text {line }}=I_{p h}=4.17\mathrm{~A}

Step-2

If they connected in  delta connection

Z_{p h}=19.56

I_{p h}=\frac{V_{p h}}{Z_{p h}}  = \frac{200}{19.56}= 10.22A

Dissipated power-

P=\sqrt{3} I_{p h}^{2} R

P=\sqrt{3} \times 10.22^{2} \times 15= 27.13KW}

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