Question

3. Simplify: sin A
sin A -cos A
COS A
sin A
cos A sin A
+ cos A
- sin A cos A​

Answer 1

Answer:

$(i) sin A = \dfrac{side opposite to \angle A}{ Hypotenuse} ... (iv) $\dfrac{sin\ 30° + tan\ 45° - cosec\ 60°}{sec\ 30° + cos\ 60° + cot\ 45°}$ ... (i) $\dfrac{sin\ 18^o}{cos\ 72^o}$ $\\$ $\dfrac{sin\ 90^o- 72^o}{cos\