3(sin^2 38 degree +sin^2 52 degree)
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3[sin^2 38 degree +cos^2(90-38)]
3(sin^2 38 degree+ cos^2 38degree)
we know that
sin^2 theta + cos^2 theta= 1
so, 3× 1= 3.
I hope it will help you.
3(sin^2 38 degree+ cos^2 38degree)
we know that
sin^2 theta + cos^2 theta= 1
so, 3× 1= 3.
I hope it will help you.
rajesh198:
Thank's
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