3 sin 3 B + 2 cos (2 B + 5)
2 cos 3 B – sin (2 B - 10)
when B = 20°
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Answer:3sin60°+2cos(45°)/2cos60°-sin30
3[√3/2]+2[1/2] /2[1/2] [√3/2]
3√3/2+√2 /3√3+2√2
hope it helps u
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