Question

3 sin 3 B + 2 cos (2 B + 5°)
2 cos 3 B - sin (2 B - 109)
when B = 20°
help plz will certainly mark u as brainliest​

Answer 1

Step-by-step explanation:

What's your doubt?

Maths

If the value of

2cos3B−sin(2B−10

∘

)

3sin3B+2cos(2B+5

∘

)

; when B= 20

∘

is 3

m

+2

2

, then find the value of m.

share

Share

Answer

Correct option is

A

3

2cos3B−sin(2B−10

∘

)

3sin3B+2cos(2B+5

∘

)

; when B = 20

∘

when, B=20

∘

2cos60

∘

−sin(30

∘

)

3sin60

∘

+2cos(45

∘

)

=

2(

2

1

)−(

2

1

)

3(

2

3

)+2(

2

1

)

=

(

2

2

)−(

2

1

)

(

2

3

3

)+(2

2

2

)

=3

3

+2

2

verified_toppr

veeresh