Math, asked by prajwal2306, 7 months ago

3 sin 3 B + 2 cos (2 B + 50)
2 cos 3 B - sin (2B - 10°)
when B = 20°.​

Answers

Answered by kartik278090
0

Answer:

3 sin 3 B + 2 cos (2 B + 50)

2 cos 3 B - sin (2B - 10°)

when B = 20°.

Answered by jaikishore65
3

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