Math, asked by padmajajammula, 11 months ago

3 sin 3B -2 cos (2B+5°)/2cos3 B - sin(2B-10°)
when B =20°

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Answered by Anonymous

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Answered by roshni5052

Answer:

3sin60°+2cos(45°)/2cos60°-sin30

3[√3/2]+2[1/2] /2[1/2] [√3/2]

3√3/2+√2 /3√3+2√2

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