3 sin 3B -2 cos (2B+5°)/2cos3 B - sin(2B-10°)
when B =20°
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Answer:
3sin60°+2cos(45°)/2cos60°-sin30
3[√3/2]+2[1/2] /2[1/2] [√3/2]
3√3/2+√2 /3√3+2√2
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