Question

3 sin θ = 4cos θ find the value of 4sin^2  θ - 3 cos^2 θ +2​

Answer 1

Answer:

$\huge\purple {\mathfrak{Bonjour Mate!}}$

3sin² x + 4cos² x = 3sin² x + (3cos² x + cos² x)

= 3sin² x + 3cos² x + cos² x

= (3sin² x + 3cos² x) + cos² x

= 3(cos² x + sin² x) + cos² x

Since we have the trigonometric identity: cos² x + sin² x = 1, substituting, we get:

= 3(1) + cos² x

Therefore, we have the result:

= 3 + cos² x

Answer 2

Answer:

$\huge\purple {\mathfrak{Answer }}$

Step-by-step explanation:

please refer to above attachment..☺️