3(Sin^6 theta +cos^6theta)-2(sin^4theta +cos^4theta) -1=0
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Answer:
Step-by-step explanation:
3(sin∧6theta +cos∧6theta)-2(sin∧4theta+cos∧4theta)-1
3-2-1 (∵sin²theta+cos²theta=1)
∴3(sin∧6theta+cos∧theta)-2(sin∧4theta+cos∧theta)-1=0
Hence proved
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