Question

3 sin 60 - 4 sin cube 60​

Answer 1

Answer:

$3 \sin(60) - 4 \sin {}^{3} (60)$

Value of sin 60 is root 3/2

$3 \times \frac{ \sqrt{3} }{2} - 4( \frac{ \sqrt{3} }{2} ) {}^{3}$

$\frac{3 \sqrt{3} }{2} - \frac{12 \sqrt{3} }{8}$

$\frac{12 \sqrt{3} - 12 \sqrt{3} }{8}$

$\frac{0}{8}$

Answer is 0.