Math, asked by ajayameta1971, 3 months ago

3 sin 60 degree - 2 cos square 30- 1

Answers

Answered by muskanperween225
0

Step-by-step explanation:

3 sin 60 Degree - 2 cos^2 30degree - 1

 = 3 \times  \frac{ \sqrt{3} }{2}  - 2 \times  ({ \frac{ \sqrt{3} }{2}) }^{2}  - 1

 =  \frac{3 \sqrt{3} }{2}  - 2 \times  \frac{3}{4}  - 1

 =  \frac{3 \sqrt{3} }{2}  -  \frac{3}{2}  - 1

 =  \frac{3 \sqrt{3} - 3 - 2 }{2}

 =  \frac{3 \sqrt{3}  - 5}{2}

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