Question

3 sin a - 4 COS a = 0. Find the value of tan a, sec a and cosec a, where a is an acute angle One)
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Answer 1

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3 sin α – 4 cos α = 0

∴ 3 sin α = 4 cos α

∴ sinα / cos α = 4/3

∴ tanα = 4/3

We know that,

tanα = y/x = 4/3

∴ y = 4 and x = 3

r = √(x2+y2 )

∴ r =√((3)2+(4)2 )

∴ r =√(9+16)

∴ r =√25

∴ r = 5

sec α = r/x = 5/3

cosec α = r/y = 5/4

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