Math, asked by sdfsfs693, 9 months ago

√3 sin theta -cos theta =0 then 2 tan theta /1-tan^2 theta

Answers

Answered by sai921603
3

Answer:

from given,(3)^1/2 sin theta=cos theta

tan theta=1/(3)^1/2

theta=30°

therefore, 2tan theta/1-tan^2 theta

=2/(3)^1/3/1-1/3

=2/(3)^1/2/2/3

=(3)^1/2

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