√3 sin theta -cos theta =0 then 2 tan theta /1-tan^2 theta
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Answer:
from given,(3)^1/2 sin theta=cos theta
tan theta=1/(3)^1/2
theta=30°
therefore, 2tan theta/1-tan^2 theta
=2/(3)^1/3/1-1/3
=2/(3)^1/2/2/3
=(3)^1/2
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