Question

√3/sin20° -1/cos20° =4​

Answer 1

$Using (3sinθ−4sin </p><p>3</p><p> θ)=sin 3θ, we get</p><p></p><p>(3sin20 </p><p>0</p><p> −4sin </p><p>3</p><p> 20 </p><p>0</p><p> )=sin60 </p><p>0</p><p> = </p><p>2</p><p>3</p><p> </p><p> </p><p>$

Answer 2

Answer:

this is the easy way to solve