Question

3 sin30degree-4sin³30degree​

Answer 1

THE ANSWER IS 1 HOPE THIS HELPS YOU MATE.....

Answer 2

We can use:

$3 \sin( \alpha ) - 4 { \sin }^{3} ( \alpha) = \sin(3 \alpha )$

Which gives,

$\sin(3 \times {30}^{0} )$

$= \sin( {120}^{0} )$

$= \sin( {90}^{0} + {30}^{0} )$

$= \cos( {30}^{0} )$

$= \frac{ \sqrt{3} }{2}$

Hence, this is the required answer.

Hope it helps!