3 sinAis equal to 4cos A find the value of tan2A-Sec2A
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Answer:
1/7
Step-by-step explanation:
since we know tan2A= 2tanA/1-tan²A
and sec 2A= sec²A/2-sec²A
also given that 3sinA=4cosA
therefore tanA =4/3
and also sec A is given by
since cosA from given value=3/5
so secA=5/3
solving then
tan2A= (2*4/3)/1-(4/3)²= -24/7
and sec2A= (5/3)²/2-(5/3)²= -25/7
therefore given ques ans is. -24/7-(-25/7)= 1/7
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