Question

3 sino +40os o then what is the
value of 4sino- 3coso .​

Answer 1

We have,

3sinθ+4cosθ=5 ………. (1)

On squaring both sides, we get

(3sinθ+4cosθ) 2=5 ^2

9sin 2θ+16cos 2θ+24sinθcosθ=25

9(1−cos 2 θ)+16(1−sin 2 θ)+12×2sinθcosθ=25

9−9cos 2 θ+16−16sin 2 θ+12×2sinθcosθ=25

25−9cos 2 θ−16sin 2θ+12×2sinθcosθ=25

9cos 2 θ+16sin 2θ−12×2sinθcosθ=0

3cosθ−4sinθ) 2=0

3cosθ−4sinθ=0

Hence, the value is 0.

This is your answer

Hope this helps you