Question

3 sino Coso thay fano 3 14 sin²o 2 안 P-1​

Answer 1

Answer:

pls write properly

i can't understand

thanks

Answer 2

Step-by-step explanation:

1 + sin2θ = 3 sin θ cos θ

Divide by cos2 θ to both the sides, we get

⇒ sec2 θ + tan2 θ = 3 tan θ

⇒ 1+ tan2 θ+ tan2 θ = 3tan θ

⇒ 2 tan2 θ –3tan θ +1 = 0

Let tanθ = x

⇒ 2x2 – 3x +1 = 0

⇒ 2x2 – 2x – x +1 = 0

⇒ 2x ( x – 1) – 1(x – 1) = 0

⇒ (2x – 1)(x – 1) = 0

Putting each of the factor = 0, we get

⇒ x = 1 or 1/2

And above, we let tan θ = x

⇒ tanθ = 1 or 1/2