Math, asked by nik541, 1 year ago

3 sinx +4 cos ax = 7 has at least one solution then the possible values of a​

Answers

Answered by amitnrw
7

Answer:

a = 4n

values of  a  =  0  , 4 , 8  ,  12

Step-by-step explanation:

3 sinx +4 cos ax = 7 has at least one solution then the possible values of a

Only Possible solution

when Sinx = 1  

& cosax = 1

Sinx = 1    when x = π/2

cosax = 1 = when  ax = 2πn

aπ/2 = 2nπ

=> a = 4n

Then values of  a  =  0  , 4 , 8  ,  12

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