Math, asked by kattabhavana2001, 4 months ago

3[sinx-cosx]4+6[sinx+cosx]2+4[sin6x+cos6x]=? put x=90

Answers

Answered by saxenaanjali016
0

Step-by-step explanation:

=3[sin90- cos90]4+6[sin90+cos90]2+4[6(sin90+cos90)]

=3[1-0]10[1+0]6[6(1+0)]

=3*1*10*1*6*6

=1080.

Answered by rkeerthi913
0

Answer:

28 is the answer

Step-by-step explanation:

because 3(1-0)4+6(1+0)2+4(0+1)

=12+12+4

=28

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