Question

3 solutions for 2x+3y=1​

Answer 1

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Three solutions for 2x + 3y = 1

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SOLUTION 1,

Let x = 1

→ 2(1) + 3y = 1

→ 2 + 3y = 1

→ 3y = 1 - 2

→ 3y = -1

→ y = -1/3

Therefore, x = 1 & y = -1/3.

SOLUTION 2,

Let x = 2

→ 2(2) + 3y = 1

→ 4 + 3y = 1

→ 3y = 1 - 4

→ 3y = -3

→ y = -3/3

→ y = -1

Therefore, x = 2 & y = -1.

SOLUTION 3,

Let x = 3

→ 2(3) + 3y = 1

→ 6 + 3y = 1

→ 3y = 1 - 6

→ 3y = -5

→ y = -5/3

Therefore, x = 3 & y = -5/3.

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Answer 2

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SOLUTION 1 :

Let x = 1

2(1) + 3y = 1

+ 2 + 3y = 1

» 3y = 1-2

+ 3y = -1

+y = -1/3

Therefore, x =1 x y = -1/3.

SOLUTION 2 :

Let x = 2

• 2(2) + 3y = 1

» 4 + 3y = 1

+ 3y = 1-4

- 3y = -3

+ y = -3/3

- y = -1

Therefore, x = 2 & y = -1.

SOLUTION 3 :

Let x = 3

- 2(3) + 3y = 1

- 6+ 3y = 1

+ 3y = 1-6

+ 3y = -5 =

→ y = -5/3

Therefore, x = 3 & y = -5/3.