Question

3) Solve 2y²+2y=3 in formula method in quadratic equation​

Answer 1

Answer:

hi friend

here is ur ans

2y^2+2y=3

2y^2+2y-3=0

ax^2+bx+c=0

a=2,b=2,c=-3

y= -b±√b^2-4ac/2a

D=b^2-4ac=2^2-4.2.-3

=4-(-24)=4+24=28

y=. -2±√D/2.2

-2±√28/4=-2±2√7/4

so the answer is -2 ±2√7/4..........

thanku dear

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