3. Solve 8x +3<4x + 7
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Answer:
8x+3<4x+7
subtracting 3 both sides
8x+3-3<4x+7-3
8x<4x+4
subtracting 4x both sides
8x-4x<4x-4x+4
4x<4
divide by 4 both sides
x<1
Answered by
0
Answer:
Let write que in quadratic equation.
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