Math, asked by naiksada1974, 4 months ago

3. Solve 8x +3<4x + 7​

Answers

Answered by akpateriya
0

Answer:

8x+3<4x+7

subtracting 3 both sides

8x+3-3<4x+7-3

8x<4x+4

subtracting 4x both sides

8x-4x<4x-4x+4

4x<4

divide by 4 both sides

x<1

Answered by Ajit4294
0

Answer:

Let write que in quadratic equation.

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