Question

3.solve: a) 15 (x-1)+4 (x+3)=2 (7+x)
b)4×+3=2×+7
4.solve:a)8p-5/7p+1=-2/4
b)3(t-4)=5 (2t-3)

answer this for 20 points​

Answer 1

Answer:

A) Given: 15(x-1)+4(x+3)=2(7+x)15(x−1)+4(x+3)=2(7+x)

To Find: Find the value of x

Solution:

15(x-1)+4(x+3)=2(7+x)15(x−1)+4(x+3)=2(7+x)

15x-15+4x+12=14+2x15x−15+4x+12=14+2x

19x-3=14+2x19x−3=14+2x

19x-2x=14+319x−2x=14+3

17x=1717x=17

x=\frac{17}{17}x=

17

17

x=1x=1

B) 4×+3=2×+7

4x-2x=7-3

2x=4

x=4/2

x=2

.

4)A) Given,

7p+1

8p−5

=

4

−2

4(8p−5)=−2(7p+1)

32p−20=−14p−2

46p=18

p=

46

18

=

23

9

B)Given, 3(t−4)=5(2t−3)

3t−12=10t−15

3t-10t=-15+12

-7t=-3

t=-3/7

Answer 2

Answer:

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