Question

3.solve: a) 15 (x-1)+4 (x+3)=2 (7+x)
b)4×+3=2×+7
4.solve:a)8p-5/7p+1=-2/4
b)3(t-4)=5 (2t-3)
Please answer this question this is urgent PLEASE HELP
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Answer 1

Answer:

$\sf15(x−1)+4(x+3)=2(7+x)$

$\sf15x−15+4x+12=14+2x$

$\sf19x−3=14+2x$

$\sf17x=17$

$\sf \: x=1$

Answer 2

Answer:

.

$3. \: solve: a)15(x - 1) + 4(x + 3) = 2(7 + x) \\ \\ 15 - 15x + 4x + 12 = 14 + 2x \\ \\ 27 - 11x = 14 + 2x \\ \\ - 11x - 2x = 14 - 27 \\ \\ - 13x = - 13 \\ \\ x = \frac{ - 13}{ - 13} = \frac{ - 1}{ - 1} = 1 \\ \\ x = 1 \\ \\ \\ \\ b)4x + 3 = 2x + 7 \\ 4x - 2x = 7 - 3 \\ 2x = 4 \\ x = \frac{4}{2} = 2 \\ x = 2 \\ \\ \\ 4.solve: \: a) \frac{8p - 5}{7p + 1} = \frac{ - 2}{4} \\(cross \: multiply) \\ \\ 4(8p - 5) = - 2(7p + 1) \\ 32p - 20 = - 14p + 2 \\ 32p + 14p = 2 + 20 \\ 46p = 22 \\ \\ p = \frac{22}{46} = \frac{11}{23} \\ \\ \\ \\ b) \: \: \: 3(t - 4) = 5(2t - 3) \\ 3t - 12 = 10t - 15 \\ - 12 + 15 = 10t - 3t \\ 3 = 7t \\ \\ t = \frac{3}{7}$

Step-by-step explanation:

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