Math, asked by jacksonlawrence, 5 months ago

3. Solve any one of the following difference equations :

(1) Yx+2 - 4 yx+1 + 4 yx = 2*
(2) Yx+2 - 5 Yx+1 + 6 yx = 36

Answers

Answered by varshitha349
1

1) Yx³+2-4+4+1= 2

Yx³-2+4+1=2

Yx³+2+1=2

Yx³+3=2

Hope this helps you..

you only said one so that's y I solved one....

thankyou..

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Answered by saidmmasaidamma84
2

Answer:

if p(x)=0

=yx+2-4yx+1+yx=2

=y(0)+2y(0)+1y(0)=2

= y+2y+1y=2

= y²+3\2

if p(x)=0

= yx+2-5yx+1+6yx=36

=y(0)+2-5y(0)+1+6y(0)=36

=y+3y+1+6y=36

=y²+3+7y=36

= y²+10=36

=y²=36\10

I hope it helpful for you..........

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