Question

3. Solve for x : 3√2x2 – 13x + 5√2 = 0

Answer 1

Answer:

Here is your answer ✌!

$3 \sqrt{2} {x}^{2} - 13x + 5 \sqrt{2} \\ = > 3 \sqrt{2} {x}^{2} - 10x - 3 x+ 5 \sqrt{2} \\ = > \sqrt{2}x(3x - 5 \sqrt{2} ) - 1(3x - 5 \sqrt{2} ) \\ = > ( \sqrt{2}x - 1)(3x - 5 \sqrt{2} ) \\ now \sqrt{2} x - 1 = 0 \\ = x = \frac{1}{</strong><strong>/</strong><strong>2</strong><strong>} \\ = > 3x - 5 \sqrt{2} = 0 \\ = x = \frac{5 \sqrt{2} }{3}$

hope it helps u ✌!

Answer 2

3√2x2 - 13x + 5√2 = 0

3√2x2 - 10x - 3x + 5√2 = 0

√2x(3x - 5√2) - 1(3x - 5√2) = 0

(√2x - 1) (3x - 5√2) = 0

If √2x - 1 = 0. then x = 1/√2

If 3x - 5√2 = 0. then x = 5√2/3

so , x = 1/√2 and 5√2/3