Question

3. Solve sin2Q-sin4Q+sin6Q=0

Answer 1

Step-by-step explanation:

sin Q + sin 2Q=1

.....> sin Q= cos 2 Q [as, 1-sin 2Q

=cos 2 Q]....(।)

so,

= cos 2 Q +(cos2Q) 2 [as, cos 4Q

=(cos 2Q)2]

=sin Q + sin 2 Q

= 1...(ans)......