Math, asked by saisamathapatil, 9 months ago

3. Solve the equation
3x3-4x2+x+88 = 0, one root being 2+ 7
1)​

Answers

Answered by 4444priyanshu
1

Answer:

-44

Step-by-step explanation:

3x*3-4x*2+x=-88

9x-8x+x=-88

x+x=-88

2x=-88

x=-88/2

x=-44(answer)

Answered by nithins7676
2

Answer:roots are (2+root7i) (2-root7i) (-8/3)

Step-by-step explanation: if one root is 2+root7i

then the other root is 2-root7i

cause they are conjucate pairs

let alfa be the other unknown root

SUM OF ROOTS--  (2+root7i)+(2-root7i)+ ALFA =  -(-4/3)

                            = 4+ ALFA =4/3

                        THEN, ALFA=  -8/3

HENCE, THE ANSWER IS -8/3.......

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