Question

3. Solve the following equations by trial and error method:
(i) 5p + 2 = 17 (ii) 3m - 14 = 4

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Answer 1

Answer:

p = 3 ; m = 6

Step-by-step explanation:

(i) If p = 0 then 5(0) + 2 = 17, 0 + 2 ≠ 17

If p = 1 then 5(1) + 2 = 17, 5 + 2 ≠ 17

If p = 2 then 5(2) + 2 = 17, 10 + 2 ≠ 17

If p = 3 then 5(3) + 2 = 17, 15 + 2 ≠ 17

∴ p = 3 is the solution to the given equation 5p + 2 = 17.

(ii) If m = 0 then 3(0) – 14

0 – 14 = – 14 ≠ 4

3m – 14 = 4

If m = 1 then 3(1) – 14

3 – 14 = -11

If m = 2 then 3(2) – 14

6 – 14 = – 8

If m = 3 then 3(3) – 14 = -5

If m = 4 then 3(4) – 14 = -2

If m = 5 then 3(5) – 14 = 1

If m = 6 then 3(6) – 14 = 4

LHS = RHS

∴ m = 6 is the solution to the given equation 3m – 14 = 4.

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