3. Solve the following problems.
a) Ramayya's house is at a distance of 4 km 326 m from his field. One day he
went to his field on a cart a distance of 2 k.m 850 m. and the rest of the distance
by foot. What is the distance he walked on that day?
Answers
Answered by
9
Given,
Total distance to house = 4 km 326 m = 4326 m
Distance travelled by cart = 2 km 850 m = 2850 m
Rest of the distance is travelled by foot.
Distance travelled by foot = total distance - distance travelled by cart
= 4326 - 2850
= 1476 m
Therefore, distance he walked is 1 km 476 m.
Answered by
2
Answer: distance from house to field =4k.m 326m distance traveled on a cart=2k.m 850m the total distance travelled by Ramayya=4k.m 326m subtract by 2k.m 850m the total distance travelled by Ramayya=1k.m 476m
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