Question

3) Solve the following quadratic equations.

2) 2x + 3ix + 2-0​

Answer 1

Answer:

x = i(-3±5)/4

Step-by-step explanation:

2x^2 + 3ix + 2 = 0

Using quadratic equation;

we know, x = (-b ± √b^2 - 4ac)/2

x = [-3i ± √(3i)^2 - 4x2x2]/2x2

= -3i ± √-25/4

= i(-3±5)/4