3.
Solve the following system of equation by the substitution method
x + 2y - 7 = 0
2x - y - 11 = 0
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Answer:
3x+2y=7
4x+y=6⇒y=6−4x
placing in equation (1)
3x+2(6−4x)=7
3x+12−8x=7⇒−5x+12=7
−5x=7−12⇒−5x=−5
x=1
∴ y = 6 - 4×1=2
∴ x = 1, y = 2
solution
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