Question

3. Solve: (x2-3x)² - 16 (x²-3x)-36 = 0
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Answer 1

Answer:

Step-by-step explanation:

(x2-3x)² - 16 (x²-3x)-36 = 0

(x^2)^2 - 2(x^2)(3x) + (3x)^2 - 16(x^2 - 3x) - 36 = 0

x^4 - 6x^3 + 9x^2 - 16x^2 + 48x - 36 = 0

x^4 - 6x^3 - 5x^2 + 48x -36 = 0

Used Formula

( a + b)^2 = a^2 + b^2 + 2ab