Question

3) Solve (x2 + x) (x2 + x - 2) = 24​

Answer 1

Answer:

let x2 + x = a.

then a(a - 2) = 24.

a2 -2a -24 = 0

here a = 6 or -4 .

ie., x2 + x - 6 = 0 and x2 + x + 4 = 0

on solving the first quadratic equations u will get x = 2 , -3 , and second will not exist.

Answer 2

[Checking -> Using Factorisation]

$\sf {x}^{2} −2x−24=0 \\ </strong></p><p><strong>[tex] \sf {x}^{2} −2x−24=0 \\ \sf(x−6)(x+4)=0 \\ </strong></p><p><strong>[tex] \sf {x}^{2} −2x−24=0 \\ \sf(x−6)(x+4)=0 \\ \sf \red{ x=6,−4}$

$\sf \: Since \: we \: got \: the \: \\ \: \sf \: same \: answer \: for \: both \: \\ \sf \: method, \: we \: know \: that \\ \sf \: \: our \: \red { answere \: is \: correct.}$