3 sphere of 6cm, 8cm and 10cm radii are melted to recast to form a cone of 16 cm radius . find the height of tge cone.
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Volume of sphere = 4/3πr³
volume of first sphere = 4/3 ×22/7 ×
6×6×6=905.14cm³
volume of second sphere = 4/3× 22/7×8×8×8
= 2145.52cm³
Volume of third sphere = 4/3 ×22/7×10×10×10
= 4190.47cm³
Volume of new cone = 905.14+ 2145.52+ 4190.47
= 7241.13cm³
πr²h= 7241.13
π×16×16×h = 7241.13
πh = 7241.13/16 ×16
πh = 7241.13
h = 7241.13 ×7/22
h= 2303.9cm
h = 23.03m
hope it helps u ...
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