Question

3. Starting from rest, acceleration of a particle is a = 2(t-1). The velocity of the particle at tas is (1) 15 m/sec (4) None of these (2)25 m/sec (3) 5 m/sec Where x dv a =​

Answer 1

Explanation:

a=2(t−1)

=2t−2

dtdv=2t−2

dv=(2t−2)dt

integrating both side we get,

∫dv=∫(2t−2)dt

v=t2−2t+c

=(5)2−2×5

=25−10

=15m/s