Math, asked by jhaa04081, 8 hours ago

3) State the factors of 49x2 - 121.​

Answers

Answered by manpreeeetttt
0

Answer:

Rewrite 49x2 49 x 2 as (7x)2 ( 7 x ) 2 . Rewrite 121 as 112 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=7x a = 7 x and b=11 .

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