3 students from a group of 18 students failed in the examination for the subject of Economics.
The marks obtained by the 15 students who passed are as follows:
42, 65, 53, 75, 43, 50, 68, 57, 79, 48, 51, 61, 55, 70, 64. Find the median marks of all 18
students.
Answers
ics Chapter 6 - Measures Of Central Tendency Median And Mode
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Textbook Solutions Class 11 Economics Measures Of Central Tendency Median And Mode
Sandeep_garg_(2018) Solutions for Class 11 Commerce Economics Chapter 6 Measures Of Central Tendency Median And Mode are provided here with simple step-by-step explanations. These solutions for Measures Of Central Tendency Median And Mode are extremely popular among Class 11 Commerce students for Economics Measures Of Central Tendency Median And Mode Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Sandeep_garg_(2018) Book of Class 11 Commerce Economics Chapter 6 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Sandeep_garg_(2018) Solutions. All Sandeep_garg_(2018) Solutions for class Class 11 Commerce Economics are prepared by experts and are 100% accurate.
Page No 9.74:
Question 1:
Find out the median.
S. No. 1 2 3 4 5 6 7 8 9
Marks Obtained 10 12 14 17 18 20 21 30 32
ANSWER:
10, 12, 14, 17, 18, 20, 21 30, 32
N = 9
Median=(
N+1
2
)th itemMedian=(
9+1
2
)th=5th item
Thus, Median is given by the size of the 5th item. Therefore, Median of the data so given is 18.
Page No 9.74:
Question 2:
Find the value of the median from the following data: 15, 35, 48, 46, 50, 43, 55, 49.
ANSWER:
First of all, we need to arrange the data in an ascending order. Thus, the data is presented below as:
15, 35, 43, 46, 48, 49, 50, 55
N = 8
Since the number of items in the series is even, thus the following formula is used to calculate the median.
Median=
Size of (
N
2
)th item + Size of (
N
2
+1)th item
2
=
Size of (
8
2
)th item + Size of (
8
2
+1)th item
2
=
Size of 4th item + Size of 5th item
2
=
46+48
2
=47
Thus, Median is 47.