Math, asked by sushant6367, 7 months ago

3. Subtract 2a(a’ +b²-c^2)-2abc (a+b-c) from 4a (-a+b+c).​

Answers

Answered by sanskritii82
1

Answer:

4a(-a+b+c) - {2a(a+b^2-c^2)-2ab}

-4a^2 + 4ab + 4ac - {2a^2 + 2ab^2 - 2ac^2 - 2ab}

-4a^2 + 4ab + 4ac - 2a^2 - 2ab^2 + 2ac^2 + 2ab

-4a^2 - 2a^2 + 4ab + 2ab - 2ab^2 + 4ac + 2ac^2

-6a^2 + 6ab + 6ac^3 - 2ab^2

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