Question

3 subtract root 3 whole square

Answer 1

the ans. is

3-(√3)^2=3-3=0

Answer 2

$(3-\sqrt3)^2=12-6\sqrt3$

Step-by-step explanation:

Given : Expression $(3-\sqrt3)^2$

To find : Solve the expression ?

Solution :

Using algebraic identity,

$(a-b)^2=a^2+b^2-2ab$

Here, a=3 and $b=\sqrt3$

Substitute the value,

$(3-\sqrt3)^2=(3)^2+(\sqrt3)^2-2(3)(\sqrt3)$

$(3-\sqrt3)^2=9+3-6\sqrt3$

$(3-\sqrt3)^2=12-6\sqrt3$

Therefore, $(3-\sqrt3)^2=12-6\sqrt3$

#Learn more

(-√6+√2) whole square + (√6+√2) whole square​

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