3. Sum of the ages of A and B is 33 years and the age of A is 7 less than the thrice of the
age of B. Find the ages of A and B.
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QUESTION -
Sum of the ages of A and B is 33 years and the age of A is 7 less than the thrice of the
age of B. Find the ages of A and B.
Answer -
First write the given
---->A+B=33
---->A is 7 less than the thrice of the age of B
Now form the equations from the given data
Then
A=33-B-------(1)
Moreover
A=3B-7--------(2)
Now we got 2 equation both equal to A
So put these both equation equal
Then
33-B=3B-7
33+7=3B+B
40=4B
B=10
Now put the value of B in first equation
A=33-B
A=33-10
A=23
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Answered by
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Answer:
Age of A=33
Age of B =33
Age of A is 7 less than B
Age of A= 33-7
=26
Thrice(3x) of age B
Age of A=26×3
= 78
Age of A=78
Age of B=33
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