Question

3. Sum of the digits of a two digit number is 9. The digit in the ones place is one more than three times the digit in the tens place. Find the two digit number.​

Answer 1

Answer:

Step-by-step explanation:

number be XY

given Y=1+3X

and X+Y=9

X+1+3X=9

4X+1=9

4X=9-1=8

X=8/4

X=2

Y=1+3x=1+3*2=1+6=7

XY=27