Question

3. Sum of the digits of a two-digit number is 9. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 27. What
is the two-digit number?​

Answer 1

Answer:

$\color{Green}{YOUR ANSWER}$

Let unit place be y and Tens place be X

By problem,

X+ Y = 9 .. eq(1)

By problem,

10y+x=10x+y+27

10y-y+x-10x=27

9y-9x=27

9(y-x)=9(3)

9 cuts off

y-x=3 ... eq(2)

atp

y+x= 9

y-x=3

x cuts off by add method

2y=12

y=12/2

y=6

putting value of y in eq(1)..

x+6=9

x=9-6

x=3

As we know that the two digit number is supposed to be

10x+y

10*3+6

30+6

36 <= Your ans

$\color{Red}{Please mark it as brainliest}$

Answer 2

Answer:

36 +27= 63 ANSWER

Explanation:

digits are reversed

difference is 27

sum of digits is 9

There are ten numbers whose digits add up to 9.

This happens in the table of 9

I reversed the digits and subtracted smaller number from bigger.

Search for difference 27

and we get the answer.