3. Suppose 2 kg of sugar contains 9 * 109 crystals. How many sugar crystals are there in (a) 5 kg of suga
(b) 1.2 kg of sugar
Answers
Step-by-step explanation:
If two quantities increase or decrease together in such a manner that the ratio of their corresponding values remain constant, we say that the two quantities vary directly.
In other words x and y are said to vary directly if X/y = k , where k is a positive constant.
In direct Proportion
x/y= k
x=ky
So we can find value of k from known values, and then use the formula to calculate the unknown values.
When two quantities x and y are in direct proportion (or vary directly) they are also written as x∝y.
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Solution:
I) Let sugar crystal be ‘x’
Here weight of sugar and number of sugar crystals are in direct proportion.
2/9×10^6 = 5/x
X×2= 5×9×10^6
X= (5×9×10^6)/2
X= (45 × 10^6)/2= 22.5× 10^6
X= 2.25× 10^7
Hence, number of sugar crystal is 2.25× 10^7
ii) Let sugar crystals be X.
Here weight of sugar and number of sugar crystals are in direct proportion.
2/9×10^6 = 1.2/x
X×2= 1.2×9×10^6
X= (1.2×9×10^6)/2
X= (0.6 × 9×10^6)
X= 5.4× 10^6
Hence, number of sugar crystal is = 5.4× 10^6
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