Question

3 (t-5)-16t=12-2 (t-3)

Answer 1

$\sf{3\left(t-5\right)-16t=12-2\left(t-3\right)}$

$\implies\sf{3t-15-16t=12-2t-6}$

$\implies\sf{-13t-15=-2t+18}$

$\implies\sf{-13t=-2t+33}$

$\implies\sf{-13t+2t=-2t+33+2t}$

$\implies\sf{-11t=33}$

$\implies\sf{t = 33/-11}$

$\implies\sf{t = -3}$

Answer 2

Answer:

=> The value of t = -3.

Step-by-step explanation:

Given that:-

$3 (t-5)-16t=12-2 (t-3)$

To find:- The value of the expression,

We must use the transposition method to determine the value of x:

As we have,

=> $3 (t-5)-16t=12-2 (t-3)$

First, we have to distribute the terms, on both sides:

=> $3t-15-16t=12-2t-6$

Combine the like terms,

=> $-13t - 15= 18 - 2t$

Now rearrange the terms,

=> $-13t - 15= - 2t+18$

Add both sides by $15$, we get

=> $-13t - 15+15= - 2t+18+15$

Simplifying it further,

=> $-13t = - 2t+18+15$

Add the numbers,

=> $-13t = - 2t+33$

Now add both sides by $2t$,

=> $-13t +2t= - 2t+33+2t$

=> $-11t= 33$

Now divide both sides by $-11$,

=> $t = -3$

Hence, the required solution is -3.