3 t If x=3 t^3 - 7t²+ 6t-11 is the displacement then calculate velocity at 1 second & 2 seconds ?
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As we know that velocity is equal to derivative of displacement with respect to time.
Given
displacement, x=3 t^3 - 7t²+ 6t-11
then velocity=9t^2-14t+6
velocity at 1 second is 1m/s
velocity at 2 seconds is 14m/s
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